6(z-1)-5(z+1)=8(z+1)

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Solution for 6(z-1)-5(z+1)=8(z+1) equation:


6(z-1) -5(z+1) =8(z+1)

We simplify the equation to the form, which is simple to understand
6(z-1)-5(z+1)=8(z+1)

Reorder the terms in parentheses
+(+6z-6)-5*(z+1)=8*(z+1)

Remove unnecessary parentheses
+6z-6-5+*(+z+1+)=+8+*(+z+1+)

Reorder the terms in parentheses
+6z-6+(-5z-5)=8*(z+1)

Remove unnecessary parentheses
+6z-6-5z-5=+8+*(+z+1+)

Reorder the terms in parentheses
+6z-6-5z-5=+(+8z+8)

Remove unnecessary parentheses
+6z-6-5z-5=+8z+8

We move all terms containing z to the left and all other terms to the right.
+6z-5z-8z=+8+6+5

We simplify left and right side of the equation.
-7z=+19

We divide both sides of the equation by -7 to get z.
z=-2.71428571429

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