6(z-14)-132=6

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Solution for 6(z-14)-132=6 equation: 



6(z-14)-132=6

We move all terms to the left:

6(z-14)-132-(6)=0

We add all the numbers together, and all the variables

6(z-14)-138=0

We multiply parentheses

6z-84-138=0

We add all the numbers together, and all the variables

6z-222=0

We move all terms containing z to the left, all other terms to the right

6z=222

z=222/6

z=37

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