6(z-2)=(4z-3)

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Solution for 6(z-2)=(4z-3) equation:



6(z-2)=(4z-3)
We move all terms to the left:
6(z-2)-((4z-3))=0
We multiply parentheses
6z-((4z-3))-12=0
We calculate terms in parentheses: -((4z-3)), so:
(4z-3)
We get rid of parentheses
4z-3
Back to the equation:
-(4z-3)
We get rid of parentheses
6z-4z+3-12=0
We add all the numbers together, and all the variables
2z-9=0
We move all terms containing z to the left, all other terms to the right
2z=9
z=9/2
z=4+1/2

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