6(z-3)=2(3z-9)

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Solution for 6(z-3)=2(3z-9) equation: 



6(z-3)=2(3z-9)

We move all terms to the left:

6(z-3)-(2(3z-9))=0

We multiply parentheses

6z-(2(3z-9))-18=0



We calculate terms in parentheses: -(2(3z-9)), so:

2(3z-9)

We multiply parentheses

6z-18

Back to the equation:

-(6z-18)



We get rid of parentheses

6z-6z+18-18=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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