6(z-3)=2(3z-9)

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Solution for 6(z-3)=2(3z-9) equation:



6(z-3)=2(3z-9)
We move all terms to the left:
6(z-3)-(2(3z-9))=0
We multiply parentheses
6z-(2(3z-9))-18=0
We calculate terms in parentheses: -(2(3z-9)), so:
2(3z-9)
We multiply parentheses
6z-18
Back to the equation:
-(6z-18)
We get rid of parentheses
6z-6z+18-18=0
We add all the numbers together, and all the variables
=0
z=0/1
z=0

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