6(z-3)=3(z+1)+3

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Solution for 6(z-3)=3(z+1)+3 equation:


Simplifying
6(z + -3) = 3(z + 1) + 3

Reorder the terms:
6(-3 + z) = 3(z + 1) + 3
(-3 * 6 + z * 6) = 3(z + 1) + 3
(-18 + 6z) = 3(z + 1) + 3

Reorder the terms:
-18 + 6z = 3(1 + z) + 3
-18 + 6z = (1 * 3 + z * 3) + 3
-18 + 6z = (3 + 3z) + 3

Reorder the terms:
-18 + 6z = 3 + 3 + 3z

Combine like terms: 3 + 3 = 6
-18 + 6z = 6 + 3z

Solving
-18 + 6z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-18 + 6z + -3z = 6 + 3z + -3z

Combine like terms: 6z + -3z = 3z
-18 + 3z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
-18 + 3z = 6 + 0
-18 + 3z = 6

Add '18' to each side of the equation.
-18 + 18 + 3z = 6 + 18

Combine like terms: -18 + 18 = 0
0 + 3z = 6 + 18
3z = 6 + 18

Combine like terms: 6 + 18 = 24
3z = 24

Divide each side by '3'.
z = 8

Simplifying
z = 8

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