6(z-3)=42+3z

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Solution for 6(z-3)=42+3z equation:



6(z-3)=42+3z
We move all terms to the left:
6(z-3)-(42+3z)=0
We add all the numbers together, and all the variables
6(z-3)-(3z+42)=0
We multiply parentheses
6z-(3z+42)-18=0
We get rid of parentheses
6z-3z-42-18=0
We add all the numbers together, and all the variables
3z-60=0
We move all terms containing z to the left, all other terms to the right
3z=60
z=60/3
z=20

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