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6(z-4)=3(2z-6)
We move all terms to the left:
6(z-4)-(3(2z-6))=0
We multiply parentheses
6z-(3(2z-6))-24=0
We calculate terms in parentheses: -(3(2z-6)), so:We get rid of parentheses
3(2z-6)
We multiply parentheses
6z-18
Back to the equation:
-(6z-18)
6z-6z+18-24=0
We add all the numbers together, and all the variables
-6!=0
There is no solution for this equation
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