6(z-4)=4(z+3)

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Solution for 6(z-4)=4(z+3) equation: 



6(z-4)=4(z+3)

We move all terms to the left:

6(z-4)-(4(z+3))=0

We multiply parentheses

6z-(4(z+3))-24=0



We calculate terms in parentheses: -(4(z+3)), so:

4(z+3)

We multiply parentheses

4z+12

Back to the equation:

-(4z+12)



We get rid of parentheses

6z-4z-12-24=0

We add all the numbers together, and all the variables

2z-36=0

We move all terms containing z to the left, all other terms to the right

2z=36

z=36/2

z=18

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