6(z-5)=2(z+1)

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Solution for 6(z-5)=2(z+1) equation:


Simplifying
6(z + -5) = 2(z + 1)

Reorder the terms:
6(-5 + z) = 2(z + 1)
(-5 * 6 + z * 6) = 2(z + 1)
(-30 + 6z) = 2(z + 1)

Reorder the terms:
-30 + 6z = 2(1 + z)
-30 + 6z = (1 * 2 + z * 2)
-30 + 6z = (2 + 2z)

Solving
-30 + 6z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-30 + 6z + -2z = 2 + 2z + -2z

Combine like terms: 6z + -2z = 4z
-30 + 4z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-30 + 4z = 2 + 0
-30 + 4z = 2

Add '30' to each side of the equation.
-30 + 30 + 4z = 2 + 30

Combine like terms: -30 + 30 = 0
0 + 4z = 2 + 30
4z = 2 + 30

Combine like terms: 2 + 30 = 32
4z = 32

Divide each side by '4'.
z = 8

Simplifying
z = 8

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