6*(x-4)+10=8x-5*(x-3)

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Solution for 6*(x-4)+10=8x-5*(x-3) equation: 



6(x-4)+10=8x-5(x-3)

We move all terms to the left:

6(x-4)+10-(8x-5(x-3))=0

We multiply parentheses

6x-(8x-5(x-3))-24+10=0



We calculate terms in parentheses: -(8x-5(x-3)), so:

8x-5(x-3)

We multiply parentheses

8x-5x+15

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

6x-(3x+15)-14=0

We get rid of parentheses

6x-3x-15-14=0

We add all the numbers together, and all the variables

3x-29=0

We move all terms containing x to the left, all other terms to the right

3x=29

x=29/3

x=9+2/3

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