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6x*x-12x-15=0
We add all the numbers together, and all the variables
-12x+6x*x-15=0
Wy multiply elements
6x^2-12x-15=0
a = 6; b = -12; c = -15;
Δ = b2-4ac
Δ = -122-4·6·(-15)
Δ = 504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{504}=\sqrt{36*14}=\sqrt{36}*\sqrt{14}=6\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{14}}{2*6}=\frac{12-6\sqrt{14}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{14}}{2*6}=\frac{12+6\sqrt{14}}{12} $
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