6+(-1)(2+3a)-(-4a)=-3(a-2)-4

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Solution for 6+(-1)(2+3a)-(-4a)=-3(a-2)-4 equation: 



6+(-1)(2+3a)-(-4a)=-3(a-2)-4

We move all terms to the left:

6+(-1)(2+3a)-(-4a)-(-3(a-2)-4)=0

We add all the numbers together, and all the variables

(-1)(3a+2)-(-4a)-(-3(a-2)-4)+6=0

We get rid of parentheses

(-1)(3a+2)+4a-(-3(a-2)-4)+6=0

We multiply parentheses ..

(-3a-2)+4a-(-3(a-2)-4)+6=0



We calculate terms in parentheses: -(-3(a-2)-4), so:

-3(a-2)-4

We multiply parentheses

-3a+6-4

We add all the numbers together, and all the variables

-3a+2

Back to the equation:

-(-3a+2)



We add all the numbers together, and all the variables

4a+(-3a-2)-(-3a+2)+6=0

We get rid of parentheses

4a-3a+3a-2-2+6=0

We add all the numbers together, and all the variables

4a+2=0

We move all terms containing a to the left, all other terms to the right

4a=-2

a=-2/4

a=-1/2

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