6+(1/v+1)=(2/v+2)

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Solution for 6+(1/v+1)=(2/v+2) equation: 


D( v )

v = 0

v = 0

v = 0

v in (-oo:0) U (0:+oo)

1/v+1+6 = 2/v+2 // - 2/v+2

1/v-(2/v)-2+1+6 = 0

1/v-2*v^-1-2+1+6 = 0

-1*v^-1 = -5 // : -1

v^-1 = 5

-1 < 0

1/(v^1) = 5 // * v^1

1 = 5*v^1 // : 5

1/5 = v^1

v = 1/5

v = 1/5

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