6+(2+y)=3(3-y)

Solution for 6+(2+y)=3(3-y) equation:

6+(2+y)=3(3-y)

We move all terms to the left:

6+(2+y)-(3(3-y))=0

We add all the numbers together, and all the variables

(y+2)-(3(-1y+3))+6=0

We get rid of parentheses

y-(3(-1y+3))+2+6=0


We calculate terms in parentheses: -(3(-1y+3)), so:

3(-1y+3)

We multiply parentheses

-3y+9

Back to the equation:

-(-3y+9)


We add all the numbers together, and all the variables

y-(-3y+9)+8=0

We get rid of parentheses

y+3y-9+8=0

We add all the numbers together, and all the variables

4y-1=0

We move all terms containing y to the left, all other terms to the right

4y=1

y=1/4

y=1/4