6+(3j-2)=4(1+j)

Solution for 6+(3j-2)=4(1+j) equation:

Simplifying
6 + (3j + -2) = 4(1 + j)

Reorder the terms:
6 + (-2 + 3j) = 4(1 + j)

Remove parenthesis around (-2 + 3j)
6 + -2 + 3j = 4(1 + j)

Combine like terms: 6 + -2 = 4
4 + 3j = 4(1 + j)
4 + 3j = (1 * 4 + j * 4)
4 + 3j = (4 + 4j)

Add '-4' to each side of the equation.
4 + -4 + 3j = 4 + -4 + 4j

Combine like terms: 4 + -4 = 0
0 + 3j = 4 + -4 + 4j
3j = 4 + -4 + 4j

Combine like terms: 4 + -4 = 0
3j = 0 + 4j
3j = 4j

Solving
3j = 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
3j + -4j = 4j + -4j

Combine like terms: 3j + -4j = -1j
-1j = 4j + -4j

Combine like terms: 4j + -4j = 0
-1j = 0

Divide each side by '-1'.
j = 0

Simplifying
j = 0