6+(3x+1)/8=2x+11

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Solution for 6+(3x+1)/8=2x+11 equation: 



6+(3x+1)/8=2x+11

We move all terms to the left:

6+(3x+1)/8-(2x+11)=0

We get rid of parentheses

(3x+1)/8-2x-11+6=0

We multiply all the terms by the denominator


(3x+1)-2x*8-11*8+6*8=0

We add all the numbers together, and all the variables

(3x+1)-2x*8-40=0

Wy multiply elements

(3x+1)-16x-40=0

We get rid of parentheses

3x-16x+1-40=0

We add all the numbers together, and all the variables

-13x-39=0

We move all terms containing x to the left, all other terms to the right

-13x=39

x=39/-13

x=-3

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