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6+(3x+1)/8=2x+11
We move all terms to the left:
6+(3x+1)/8-(2x+11)=0
We get rid of parentheses
(3x+1)/8-2x-11+6=0
We multiply all the terms by the denominator
(3x+1)-2x*8-11*8+6*8=0
We add all the numbers together, and all the variables
(3x+1)-2x*8-40=0
Wy multiply elements
(3x+1)-16x-40=0
We get rid of parentheses
3x-16x+1-40=0
We add all the numbers together, and all the variables
-13x-39=0
We move all terms containing x to the left, all other terms to the right
-13x=39
x=39/-13
x=-3
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