6+(3x-2x)=-3(x-5)+2(9x+4)

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Solution for 6+(3x-2x)=-3(x-5)+2(9x+4) equation: 



6+(3x-2x)=-3(x-5)+2(9x+4)

We move all terms to the left:

6+(3x-2x)-(-3(x-5)+2(9x+4))=0

We add all the numbers together, and all the variables

(+x)-(-3(x-5)+2(9x+4))+6=0

We get rid of parentheses

x-(-3(x-5)+2(9x+4))+6=0



We calculate terms in parentheses: -(-3(x-5)+2(9x+4)), so:

-3(x-5)+2(9x+4)

We multiply parentheses

-3x+18x+15+8

We add all the numbers together, and all the variables

15x+23

Back to the equation:

-(15x+23)



We get rid of parentheses

x-15x-23+6=0

We add all the numbers together, and all the variables

-14x-17=0

We move all terms containing x to the left, all other terms to the right

-14x=17

x=17/-14

x=-1+3/14

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