6+(3z+1)/8)=2z+11

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Solution for 6+(3z+1)/8)=2z+11 equation: 



6+(3z+1)/8)=2z+11

We move all terms to the left:

6+(3z+1)/8)-(2z+11)=0



Domain of the equation: 8)-(2z!=0

z∈R



We add all the numbers together, and all the variables

(3z+1)/8)-(2z+17)=0

We add all the numbers together, and all the variables

(3z+1)/8)-(2z=0

We multiply all the terms by the denominator


(3z+1)=0

We get rid of parentheses

3z+1=0

We move all terms containing z to the left, all other terms to the right

3z=-1

z=-1/3

z=-1/3

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