6+(3z+1)=2z+11

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Solution for 6+(3z+1)=2z+11 equation: 



6+(3z+1)=2z+11

We move all terms to the left:

6+(3z+1)-(2z+11)=0

We get rid of parentheses

3z-2z+1-11+6=0

We add all the numbers together, and all the variables

z-4=0

We move all terms containing z to the left, all other terms to the right

z=4

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