6+(4-m)=8(3m-5)

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Solution for 6+(4-m)=8(3m-5) equation: 



6+(4-m)=8(3m-5)

We move all terms to the left:

6+(4-m)-(8(3m-5))=0

We add all the numbers together, and all the variables

(-1m+4)-(8(3m-5))+6=0

We get rid of parentheses

-1m-(8(3m-5))+4+6=0



We calculate terms in parentheses: -(8(3m-5)), so:

8(3m-5)

We multiply parentheses

24m-40

Back to the equation:

-(24m-40)



We add all the numbers together, and all the variables

-1m-(24m-40)+10=0

We get rid of parentheses

-1m-24m+40+10=0

We add all the numbers together, and all the variables

-25m+50=0

We move all terms containing m to the left, all other terms to the right

-25m=-50

m=-50/-25

m=+2

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