6+(4/5)b=9/10b

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Solution for 6+(4/5)b=9/10b equation: 



6+(4/5)b=9/10b

We move all terms to the left:

6+(4/5)b-(9/10b)=0



Domain of the equation: 5)b!=0

b!=0/1

b!=0

b∈R





Domain of the equation: 10b)!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+4/5)b-(+9/10b)+6=0

We multiply parentheses

4b^2-(+9/10b)+6=0

We get rid of parentheses

4b^2-9/10b+6=0

We multiply all the terms by the denominator


4b^2*10b+6*10b-9=0

Wy multiply elements

40b^3+60b-9=0

We do not support ebpression: b^3

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