6+(6/(u-3))=5/(u+1)

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Solution for 6+(6/(u-3))=5/(u+1) equation: 


D( u )

u-3 = 0

u+1 = 0

u-3 = 0

u-3 = 0

u-3 = 0 // + 3

u = 3

u+1 = 0

u+1 = 0

u+1 = 0 // - 1

u = -1

u in (-oo:-1) U (-1:3) U (3:+oo)

6/(u-3)+6 = 5/(u+1) // - 5/(u+1)

6/(u-3)-(5/(u+1))+6 = 0

6/(u-3)-5*(u+1)^-1+6 = 0

6/(u-3)-5/(u+1)+6 = 0

(6*(u+1))/((u-3)*(u+1))+(-5*(u-3))/((u-3)*(u+1))+(6*(u-3)*(u+1))/((u-3)*(u+1)) = 0

6*(u+1)-5*(u-3)+6*(u-3)*(u+1) = 0

6*u^2+u-12*u-18+21 = 0

6*u^2-11*u+3 = 0

6*u^2-11*u+3 = 0

6*u^2-11*u+3 = 0

DELTA = (-11)^2-(3*4*6)

DELTA = 49

DELTA > 0

u = (49^(1/2)+11)/(2*6) or u = (11-49^(1/2))/(2*6)

u = 3/2 or u = 1/3

(u-1/3)*(u-3/2) = 0

((u-1/3)*(u-3/2))/((u-3)*(u+1)) = 0

((u-1/3)*(u-3/2))/((u-3)*(u+1)) = 0 // * (u-3)*(u+1)

(u-1/3)*(u-3/2) = 0

( u-1/3 )

u-1/3 = 0 // + 1/3

u = 1/3

( u-3/2 )

u-3/2 = 0 // + 3/2

u = 3/2

u in { 1/3, 3/2 }

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