6+(n+2)+(n+4)=51

Solution for 6+(n+2)+(n+4)=51 equation:

Simplifying
6 + (n + 2) + (n + 4) = 51

Reorder the terms:
6 + (2 + n) + (n + 4) = 51

Remove parenthesis around (2 + n)
6 + 2 + n + (n + 4) = 51

Reorder the terms:
6 + 2 + n + (4 + n) = 51

Remove parenthesis around (4 + n)
6 + 2 + n + 4 + n = 51

Reorder the terms:
6 + 2 + 4 + n + n = 51

Combine like terms: 6 + 2 = 8
8 + 4 + n + n = 51

Combine like terms: 8 + 4 = 12
12 + n + n = 51

Combine like terms: n + n = 2n
12 + 2n = 51

Solving
12 + 2n = 51

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 2n = 51 + -12

Combine like terms: 12 + -12 = 0
0 + 2n = 51 + -12
2n = 51 + -12

Combine like terms: 51 + -12 = 39
2n = 39

Divide each side by '2'.
n = 19.5

Simplifying
n = 19.5