6+(n+4)+(n+4)=51

Solution for 6+(n+4)+(n+4)=51 equation:

Simplifying
6 + (n + 4) + (n + 4) = 51

Reorder the terms:
6 + (4 + n) + (n + 4) = 51

Remove parenthesis around (4 + n)
6 + 4 + n + (n + 4) = 51

Reorder the terms:
6 + 4 + n + (4 + n) = 51

Remove parenthesis around (4 + n)
6 + 4 + n + 4 + n = 51

Reorder the terms:
6 + 4 + 4 + n + n = 51

Combine like terms: 6 + 4 = 10
10 + 4 + n + n = 51

Combine like terms: 10 + 4 = 14
14 + n + n = 51

Combine like terms: n + n = 2n
14 + 2n = 51

Solving
14 + 2n = 51

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 2n = 51 + -14

Combine like terms: 14 + -14 = 0
0 + 2n = 51 + -14
2n = 51 + -14

Combine like terms: 51 + -14 = 37
2n = 37

Divide each side by '2'.
n = 18.5

Simplifying
n = 18.5