6+-8=2(2+t1)

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Solution for 6+-8=2(2+t1) equation: 



6+-8=2(2+t1)

We move all terms to the left:

6+-8-(2(2+t1))=0

We add all the numbers together, and all the variables

-(2(t+2))+6-8+=0

We add all the numbers together, and all the variables

-(2(t+2))=0



We calculate terms in parentheses: -(2(t+2)), so:

2(t+2)

We multiply parentheses

2t+4

Back to the equation:

-(2t+4)



We get rid of parentheses

-2t-4=0

We move all terms containing t to the left, all other terms to the right

-2t=4

t=4/-2

t=-2

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