6+0.5y=-2(3-1/4y

Solution for 6+0.5y=-2(3-1/4y equation:

6+0.5y=-2(3-1/4y

We move all terms to the left:

6+0.5y-(-2(3-1/4y)=0


Domain of the equation: 4y)+6!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

0.5y-(-2(-1/4y+3)+6=0

We multiply all the terms by the denominator


(0.5y)*4y+3)+6-(-2(-1=0

We add all the numbers together, and all the variables

(+0.5y)*4y+3)+6-(-2(-1=0

We add all the numbers together, and all the variables

(+0.5y)*4y=0

We multiply parentheses

0y^2=0

We add all the numbers together, and all the variables

y^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{2}=0$