6+1/39x-9)=1/2(2-x)

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Solution for 6+1/39x-9)=1/2(2-x) equation: 



6+1/39x-9)=1/2(2-x)

We move all terms to the left:

6+1/39x-9)-(1/2(2-x))=0



Domain of the equation: 39x!=0

x!=0/39

x!=0

x∈R





Domain of the equation: 2(2-x))+6!=0

x∈R



We add all the numbers together, and all the variables

1/39x-9)-(1/2(-1x+2))+6=0

We calculate fractions


(2x(-)/(78x^2(-)+(-9)-(1*39x)/(78x^2(-)=0



We calculate terms in parentheses: +(2x(-)/(78x^2(-)+(-9)-(1*39x)/(78x^2(-), so:

2x(-)/(78x^2(-)+(-9)-(1*39x)/(78x^2(-

We can not solve this equation

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