6+10d+19=2(3d+4)-1

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Solution for 6+10d+19=2(3d+4)-1 equation: 



6+10d+19=2(3d+4)-1

We move all terms to the left:

6+10d+19-(2(3d+4)-1)=0

We add all the numbers together, and all the variables

10d-(2(3d+4)-1)+25=0



We calculate terms in parentheses: -(2(3d+4)-1), so:

2(3d+4)-1

We multiply parentheses

6d+8-1

We add all the numbers together, and all the variables

6d+7

Back to the equation:

-(6d+7)



We get rid of parentheses

10d-6d-7+25=0

We add all the numbers together, and all the variables

4d+18=0

We move all terms containing d to the left, all other terms to the right

4d=-18

d=-18/4

d=-4+1/2

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