6+12z-4=7z+3+4

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Solution for 6+12z-4=7z+3+4 equation: 



6+12z-4=7z+3+4

We move all terms to the left:

6+12z-4-(7z+3+4)=0

We add all the numbers together, and all the variables

12z-(7z+7)+6-4=0

We add all the numbers together, and all the variables

12z-(7z+7)+2=0

We get rid of parentheses

12z-7z-7+2=0

We add all the numbers together, and all the variables

5z-5=0

We move all terms containing z to the left, all other terms to the right

5z=5

z=5/5

z=1

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