6+12z-4=7z+34-3z

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Solution for 6+12z-4=7z+34-3z equation: 



6+12z-4=7z+34-3z

We move all terms to the left:

6+12z-4-(7z+34-3z)=0

We add all the numbers together, and all the variables

12z-(4z+34)+6-4=0

We add all the numbers together, and all the variables

12z-(4z+34)+2=0

We get rid of parentheses

12z-4z-34+2=0

We add all the numbers together, and all the variables

8z-32=0

We move all terms containing z to the left, all other terms to the right

8z=32

z=32/8

z=4

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