6+2(2u-1)=-5(2u-2)+6u

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Solution for 6+2(2u-1)=-5(2u-2)+6u equation: 



6+2(2u-1)=-5(2u-2)+6u

We move all terms to the left:

6+2(2u-1)-(-5(2u-2)+6u)=0

We multiply parentheses

4u-(-5(2u-2)+6u)-2+6=0



We calculate terms in parentheses: -(-5(2u-2)+6u), so:

-5(2u-2)+6u

We add all the numbers together, and all the variables

6u-5(2u-2)

We multiply parentheses

6u-10u+10

We add all the numbers together, and all the variables

-4u+10

Back to the equation:

-(-4u+10)



We add all the numbers together, and all the variables

4u-(-4u+10)+4=0

We get rid of parentheses

4u+4u-10+4=0

We add all the numbers together, and all the variables

8u-6=0

We move all terms containing u to the left, all other terms to the right

8u=6

u=6/8

u=3/4

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