6+2(2u-2)=-2(6u-4)+u

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Solution for 6+2(2u-2)=-2(6u-4)+u equation: 



6+2(2u-2)=-2(6u-4)+u

We move all terms to the left:

6+2(2u-2)-(-2(6u-4)+u)=0

We multiply parentheses

4u-(-2(6u-4)+u)-4+6=0



We calculate terms in parentheses: -(-2(6u-4)+u), so:

-2(6u-4)+u

We add all the numbers together, and all the variables

u-2(6u-4)

We multiply parentheses

u-12u+8

We add all the numbers together, and all the variables

-11u+8

Back to the equation:

-(-11u+8)



We add all the numbers together, and all the variables

4u-(-11u+8)+2=0

We get rid of parentheses

4u+11u-8+2=0

We add all the numbers together, and all the variables

15u-6=0

We move all terms containing u to the left, all other terms to the right

15u=6

u=6/15

u=2/5

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