6+2(3j-12)=4(1+j)

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Solution for 6+2(3j-12)=4(1+j) equation:


Simplifying
6 + 2(3j + -12) = 4(1 + j)

Reorder the terms:
6 + 2(-12 + 3j) = 4(1 + j)
6 + (-12 * 2 + 3j * 2) = 4(1 + j)
6 + (-24 + 6j) = 4(1 + j)

Combine like terms: 6 + -24 = -18
-18 + 6j = 4(1 + j)
-18 + 6j = (1 * 4 + j * 4)
-18 + 6j = (4 + 4j)

Solving
-18 + 6j = 4 + 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
-18 + 6j + -4j = 4 + 4j + -4j

Combine like terms: 6j + -4j = 2j
-18 + 2j = 4 + 4j + -4j

Combine like terms: 4j + -4j = 0
-18 + 2j = 4 + 0
-18 + 2j = 4

Add '18' to each side of the equation.
-18 + 18 + 2j = 4 + 18

Combine like terms: -18 + 18 = 0
0 + 2j = 4 + 18
2j = 4 + 18

Combine like terms: 4 + 18 = 22
2j = 22

Divide each side by '2'.
j = 11

Simplifying
j = 11

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