6+2(3j-2)=2(-5+4u)

Solution for 6+2(3j-2)=2(-5+4u) equation:

Simplifying
6 + 2(3j + -2) = 2(-5 + 4u)

Reorder the terms:
6 + 2(-2 + 3j) = 2(-5 + 4u)
6 + (-2 * 2 + 3j * 2) = 2(-5 + 4u)
6 + (-4 + 6j) = 2(-5 + 4u)

Combine like terms: 6 + -4 = 2
2 + 6j = 2(-5 + 4u)
2 + 6j = (-5 * 2 + 4u * 2)
2 + 6j = (-10 + 8u)

Solving
2 + 6j = -10 + 8u

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6j = -10 + -2 + 8u

Combine like terms: 2 + -2 = 0
0 + 6j = -10 + -2 + 8u
6j = -10 + -2 + 8u

Combine like terms: -10 + -2 = -12
6j = -12 + 8u

Divide each side by '6'.
j = -2 + 1.333333333u

Simplifying
j = -2 + 1.333333333u