6+2(3j-2)=4(1+j

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Solution for 6+2(3j-2)=4(1+j equation: 



6+2(3j-2)=4(1+j

We move all terms to the left:

6+2(3j-2)-(4(1+j)=0

We add all the numbers together, and all the variables

2(3j-2)-(4(j+1)+6=0

We multiply parentheses

6j-(4(j+1)+6-4=0

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