6+2(3j-2)=4+(1+j)

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Solution for 6+2(3j-2)=4+(1+j) equation:


Simplifying
6 + 2(3j + -2) = 4 + (1 + j)

Reorder the terms:
6 + 2(-2 + 3j) = 4 + (1 + j)
6 + (-2 * 2 + 3j * 2) = 4 + (1 + j)
6 + (-4 + 6j) = 4 + (1 + j)

Combine like terms: 6 + -4 = 2
2 + 6j = 4 + (1 + j)

Remove parenthesis around (1 + j)
2 + 6j = 4 + 1 + j

Combine like terms: 4 + 1 = 5
2 + 6j = 5 + j

Solving
2 + 6j = 5 + j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-1j' to each side of the equation.
2 + 6j + -1j = 5 + j + -1j

Combine like terms: 6j + -1j = 5j
2 + 5j = 5 + j + -1j

Combine like terms: j + -1j = 0
2 + 5j = 5 + 0
2 + 5j = 5

Add '-2' to each side of the equation.
2 + -2 + 5j = 5 + -2

Combine like terms: 2 + -2 = 0
0 + 5j = 5 + -2
5j = 5 + -2

Combine like terms: 5 + -2 = 3
5j = 3

Divide each side by '5'.
j = 0.6

Simplifying
j = 0.6

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