6+2(3p-2)=4(1+p)

Solution for 6+2(3p-2)=4(1+p) equation:

6+2(3p-2)=4(1+p)

We move all terms to the left:

6+2(3p-2)-(4(1+p))=0

We add all the numbers together, and all the variables

2(3p-2)-(4(p+1))+6=0

We multiply parentheses

6p-(4(p+1))-4+6=0


We calculate terms in parentheses: -(4(p+1)), so:

4(p+1)

We multiply parentheses

4p+4

Back to the equation:

-(4p+4)


We add all the numbers together, and all the variables

6p-(4p+4)+2=0

We get rid of parentheses

6p-4p-4+2=0

We add all the numbers together, and all the variables

2p-2=0

We move all terms containing p to the left, all other terms to the right

2p=2

p=2/2

p=1