6+2(3v-5)=-4(2v-3)+4v

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Solution for 6+2(3v-5)=-4(2v-3)+4v equation:



6+2(3v-5)=-4(2v-3)+4v
We move all terms to the left:
6+2(3v-5)-(-4(2v-3)+4v)=0
We multiply parentheses
6v-(-4(2v-3)+4v)-10+6=0
We calculate terms in parentheses: -(-4(2v-3)+4v), so:
-4(2v-3)+4v
We add all the numbers together, and all the variables
4v-4(2v-3)
We multiply parentheses
4v-8v+12
We add all the numbers together, and all the variables
-4v+12
Back to the equation:
-(-4v+12)
We add all the numbers together, and all the variables
6v-(-4v+12)-4=0
We get rid of parentheses
6v+4v-12-4=0
We add all the numbers together, and all the variables
10v-16=0
We move all terms containing v to the left, all other terms to the right
10v=16
v=16/10
v=1+3/5

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