6+2(3x+1)=2(2X+8)

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Solution for 6+2(3x+1)=2(2X+8) equation: 



6+2(3x+1)=2(2x+8)

We move all terms to the left:

6+2(3x+1)-(2(2x+8))=0

We multiply parentheses

6x-(2(2x+8))+2+6=0



We calculate terms in parentheses: -(2(2x+8)), so:

2(2x+8)

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

6x-(4x+16)+8=0

We get rid of parentheses

6x-4x-16+8=0

We add all the numbers together, and all the variables

2x-8=0

We move all terms containing x to the left, all other terms to the right

2x=8

x=8/2

x=4

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