6+2(4b-10)=-4(-3b-1)-10b

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Solution for 6+2(4b-10)=-4(-3b-1)-10b equation: 



6+2(4b-10)=-4(-3b-1)-10b

We move all terms to the left:

6+2(4b-10)-(-4(-3b-1)-10b)=0

We multiply parentheses

8b-(-4(-3b-1)-10b)-20+6=0



We calculate terms in parentheses: -(-4(-3b-1)-10b), so:

-4(-3b-1)-10b

We add all the numbers together, and all the variables

-10b-4(-3b-1)

We multiply parentheses

-10b+12b+4

We add all the numbers together, and all the variables

2b+4

Back to the equation:

-(2b+4)



We add all the numbers together, and all the variables

8b-(2b+4)-14=0

We get rid of parentheses

8b-2b-4-14=0

We add all the numbers together, and all the variables

6b-18=0

We move all terms containing b to the left, all other terms to the right

6b=18

b=18/6

b=3

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