6+2(4x-7)=-2(5x-4)+8x

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Solution for 6+2(4x-7)=-2(5x-4)+8x equation: 



6+2(4x-7)=-2(5x-4)+8x

We move all terms to the left:

6+2(4x-7)-(-2(5x-4)+8x)=0

We multiply parentheses

8x-(-2(5x-4)+8x)-14+6=0



We calculate terms in parentheses: -(-2(5x-4)+8x), so:

-2(5x-4)+8x

We add all the numbers together, and all the variables

8x-2(5x-4)

We multiply parentheses

8x-10x+8

We add all the numbers together, and all the variables

-2x+8

Back to the equation:

-(-2x+8)



We add all the numbers together, and all the variables

8x-(-2x+8)-8=0

We get rid of parentheses

8x+2x-8-8=0

We add all the numbers together, and all the variables

10x-16=0

We move all terms containing x to the left, all other terms to the right

10x=16

x=16/10

x=1+3/5

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