6+2(4y-3)=40

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Solution for 6+2(4y-3)=40 equation: 


Simplifying
6 + 2(4y + -3) = 40

Reorder the terms:
6 + 2(-3 + 4y) = 40
6 + (-3 * 2 + 4y * 2) = 40
6 + (-6 + 8y) = 40

Combine like terms: 6 + -6 = 0
0 + 8y = 40
8y = 40

Solving
8y = 40

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Divide each side by '8'.
y = 5

Simplifying
y = 5

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