6+2(4z-7)=3(2z+4)

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Solution for 6+2(4z-7)=3(2z+4) equation: 



6+2(4z-7)=3(2z+4)

We move all terms to the left:

6+2(4z-7)-(3(2z+4))=0

We multiply parentheses

8z-(3(2z+4))-14+6=0



We calculate terms in parentheses: -(3(2z+4)), so:

3(2z+4)

We multiply parentheses

6z+12

Back to the equation:

-(6z+12)



We add all the numbers together, and all the variables

8z-(6z+12)-8=0

We get rid of parentheses

8z-6z-12-8=0

We add all the numbers together, and all the variables

2z-20=0

We move all terms containing z to the left, all other terms to the right

2z=20

z=20/2

z=10

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