6+2(c+4)=4(c+2)

Solution for 6+2(c+4)=4(c+2) equation:

6+2(c+4)=4(c+2)

We move all terms to the left:

6+2(c+4)-(4(c+2))=0

We multiply parentheses

2c-(4(c+2))+8+6=0


We calculate terms in parentheses: -(4(c+2)), so:

4(c+2)

We multiply parentheses

4c+8

Back to the equation:

-(4c+8)


We add all the numbers together, and all the variables

2c-(4c+8)+14=0

We get rid of parentheses

2c-4c-8+14=0

We add all the numbers together, and all the variables

-2c+6=0

We move all terms containing c to the left, all other terms to the right

-2c=-6

c=-6/-2

c=+3