6+2(c+4)=4(c+2)

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Solution for 6+2(c+4)=4(c+2) equation:



6+2(c+4)=4(c+2)
We move all terms to the left:
6+2(c+4)-(4(c+2))=0
We multiply parentheses
2c-(4(c+2))+8+6=0
We calculate terms in parentheses: -(4(c+2)), so:
4(c+2)
We multiply parentheses
4c+8
Back to the equation:
-(4c+8)
We add all the numbers together, and all the variables
2c-(4c+8)+14=0
We get rid of parentheses
2c-4c-8+14=0
We add all the numbers together, and all the variables
-2c+6=0
We move all terms containing c to the left, all other terms to the right
-2c=-6
c=-6/-2
c=+3

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