6+2(x+3(x+2))=58

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Solution for 6+2(x+3(x+2))=58 equation:



6+2(x+3(x+2))=58
We move all terms to the left:
6+2(x+3(x+2))-(58)=0
We add all the numbers together, and all the variables
2(x+3(x+2))-52=0
We move all terms containing x to the left, all other terms to the right
2(x+3(x+2))=52

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