6+2(x+3(x+2))=58

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Solution for 6+2(x+3(x+2))=58 equation: 



6+2(x+3(x+2))=58

We move all terms to the left:

6+2(x+3(x+2))-(58)=0

We add all the numbers together, and all the variables

2(x+3(x+2))-52=0

We move all terms containing x to the left, all other terms to the right

2(x+3(x+2))=52

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