6+2(x+3)=4(x+2)-2

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Solution for 6+2(x+3)=4(x+2)-2 equation: 



6+2(x+3)=4(x+2)-2

We move all terms to the left:

6+2(x+3)-(4(x+2)-2)=0

We multiply parentheses

2x-(4(x+2)-2)+6+6=0



We calculate terms in parentheses: -(4(x+2)-2), so:

4(x+2)-2

We multiply parentheses

4x+8-2

We add all the numbers together, and all the variables

4x+6

Back to the equation:

-(4x+6)



We add all the numbers together, and all the variables

2x-(4x+6)+12=0

We get rid of parentheses

2x-4x-6+12=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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