6+2(x-3)=4(x+1)

Solution for 6+2(x-3)=4(x+1) equation:

6+2(x-3)=4(x+1)

We move all terms to the left:

6+2(x-3)-(4(x+1))=0

We multiply parentheses

2x-(4(x+1))-6+6=0


We calculate terms in parentheses: -(4(x+1)), so:

4(x+1)

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)


We add all the numbers together, and all the variables

2x-(4x+4)=0

We get rid of parentheses

2x-4x-4=0

We add all the numbers together, and all the variables

-2x-4=0

We move all terms containing x to the left, all other terms to the right

-2x=4

x=4/-2

x=-2