6+2(x-4)=-8x-2+10x

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Solution for 6+2(x-4)=-8x-2+10x equation: 



6+2(x-4)=-8x-2+10x

We move all terms to the left:

6+2(x-4)-(-8x-2+10x)=0

We add all the numbers together, and all the variables

2(x-4)-(2x-2)+6=0

We multiply parentheses

2x-(2x-2)-8+6=0

We get rid of parentheses

2x-2x+2-8+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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