6+2(x-4)=2(x+1)

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Solution for 6+2(x-4)=2(x+1) equation: 



6+2(x-4)=2(x+1)

We move all terms to the left:

6+2(x-4)-(2(x+1))=0

We multiply parentheses

2x-(2(x+1))-8+6=0



We calculate terms in parentheses: -(2(x+1)), so:

2(x+1)

We multiply parentheses

2x+2

Back to the equation:

-(2x+2)



We add all the numbers together, and all the variables

2x-(2x+2)-2=0

We get rid of parentheses

2x-2x-2-2=0

We add all the numbers together, and all the variables

-4!=0

There is no solution for this equation

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