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6+2(x-5)=x-3(1-2x)
We move all terms to the left:
6+2(x-5)-(x-3(1-2x))=0
We add all the numbers together, and all the variables
2(x-5)-(x-3(-2x+1))+6=0
We multiply parentheses
2x-(x-3(-2x+1))-10+6=0
We calculate terms in parentheses: -(x-3(-2x+1)), so:We add all the numbers together, and all the variables
x-3(-2x+1)
We multiply parentheses
x+6x-3
We add all the numbers together, and all the variables
7x-3
Back to the equation:
-(7x-3)
2x-(7x-3)-4=0
We get rid of parentheses
2x-7x+3-4=0
We add all the numbers together, and all the variables
-5x-1=0
We move all terms containing x to the left, all other terms to the right
-5x=1
x=1/-5
x=-1/5
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